3x^2-14x+19=2x^2-8x+10

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Solution for 3x^2-14x+19=2x^2-8x+10 equation: 



3x^2-14x+19=2x^2-8x+10

We move all terms to the left:

3x^2-14x+19-(2x^2-8x+10)=0

We get rid of parentheses

3x^2-2x^2-14x+8x-10+19=0

We add all the numbers together, and all the variables

x^2-6x+9=0

a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{2}=3$

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